65 lines
1.8 KiB
Markdown
65 lines
1.8 KiB
Markdown
[//]: # (Author: bug)
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[//]: # (Date: 2020-11-01 16:26:41)
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# Lua 数据
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##
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* 与 json 相似定义。
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* 唯一区别在于， lua 的table的key支持任意格式，所以 lua 的map 可以直接 {[key1] = value1, [key2] = value2, ,,,}
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* 
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* 注意 数据前有一个 return 语句。因为 lua 数据是当作 lua 文件加载的，每个加载后的结果当作一个记录读入。
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```xml
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<bean name="DemoType2" >
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<var name="x4" type="int" convert="DemoEnum"/>
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<var name="x1" type="bool"/>
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<var name="x5" type="long" convert="DemoEnum"/>
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<var name="x6" type="float"/>
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<var name="x7" type="double"/>
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<var name="x10" type="string"/>
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<var name="x12" type="DemoType1"/>
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<var name="x13" type="DemoEnum"/>
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<var name="x14" type="DemoDynamic" sep=","/>多态数据结构
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<var name="v2" type="vector2"/>
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<var name="v3" type="vector3"/>
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<var name="v4" type="vector4"/>
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<var name="t1" type="datetime"/>
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<var name="k1" type="array,int"/> 使用;来分隔
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<var name="k2" type="list,int"/>
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<var name="k8" type="map,int,int"/>
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<var name="k9" type="list,DemoE2" sep="," index="y1"/>
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<var name="k15" type="array,DemoDynamic" sep=","/>
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</bean>
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<table name="TbDataFromLua" value="DemoType2" input="test/lua_datas"/>
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```
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递归遍历test/lua_datas整个目录树，**按文件名排序后**依次将每个lua数据当作一个记录读入。其中1.lua文件内容如下
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```lua
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return
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{
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x1 = false,
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x2 = 2,
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x3 = 128,
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x4 = 1122,
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x5 = 112233445566,
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x6 = 1.3,
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x7 = 1122,
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x10 = "yf",
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x12 = {x1=1},
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x13 = "D",
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x14 = { __type__="DemoD2", x1 = 1, x2=3},
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v2 = {x= 1,y = 2},
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v3 = {x=0.1, y= 0.2,z=0.3},
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v4 = {x=1,y=2,z=3.5,w=4},
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t1 = "1970-01-01 00:00:00",
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k1 = {1,2},
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k2 = {2,3},
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k8 = {[2]=10,[3]=12},
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k9 = { {y1=1,y2=true}, {y1=10,y2=false} },
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k15 = { { __type__="DemoD2", x1 = 1, x2=3} },
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}
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``` |